(A+7)/4=(3a-7)/5

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Solution for (A+7)/4=(3a-7)/5 equation:



(+7)/4=(3A-7)/5
We move all terms to the left:
(+7)/4-((3A-7)/5)=0
We add all the numbers together, and all the variables
-((3A-7)/5)+7/4=0
We calculate fractions
(-((3A-7)*4)/()+()/()=0
We calculate terms in parentheses: +(-((3A-7)*4)/()+()/(), so:
-((3A-7)*4)/()+()/(
We add all the numbers together, and all the variables
-((3A-7)*4)/()+1
We multiply all the terms by the denominator
-((3A-7)*4)+1*()
We calculate terms in parentheses: -((3A-7)*4), so:
(3A-7)*4
We multiply parentheses
12A-28
Back to the equation:
-(12A-28)
We add all the numbers together, and all the variables
-(12A-28)
We get rid of parentheses
-12A+28
Back to the equation:
+(-12A+28)
We get rid of parentheses
-12A+28=0
We move all terms containing A to the left, all other terms to the right
-12A=-28
A=-28/-12
A=2+1/3

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