(3/4)x+(14/5)=(14/5)

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Solution for (3/4)x+(14/5)=(14/5) equation: 



(3/4)x+(14/5)=(14/5)

We move all terms to the left:

(3/4)x+(14/5)-((14/5))=0



Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+3/4)x+(+14/5)-((+14/5))=0

We multiply parentheses

3x^2+(+14/5)-((+14/5))=0

We get rid of parentheses

3x^2+14/5-((+14/5))=0

We calculate fractions


3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$

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