m2-7m-33=11

Solution for m2-7m-33=11 equation:

m2-7m-33=11

We move all terms to the left:

m2-7m-33-(11)=0

We add all the numbers together, and all the variables

m^2-7m-44=0

a = 1; b = -7; c = -44;
Δ = b2-4ac
Δ = -72-4·1·(-44)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-15}{2*1}=\frac{-8}{2}
=-4
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+15}{2*1}=\frac{22}{2}
=11
$