(-4-3i)(5+2i)=14

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Solution for (-4-3i)(5+2i)=14 equation: 



(-4-3i)(5+2i)=14

We move all terms to the left:

(-4-3i)(5+2i)-(14)=0

We add all the numbers together, and all the variables

(-3i-4)(2i+5)-14=0

We multiply parentheses ..

(-6i^2-15i-8i-20)-14=0

We get rid of parentheses

-6i^2-15i-8i-20-14=0

We add all the numbers together, and all the variables

-6i^2-23i-34=0

a = -6; b = -23; c = -34;
Δ = b2-4ac
Δ = -232-4·(-6)·(-34)
Δ = -287
Delta is less than zero, so there is no solution for the equation

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