(3/4)r-1+(1/2)r=11

Solution for (3/4)r-1+(1/2)r=11 equation:

(3/4)r-1+(1/2)r=11

We move all terms to the left:

(3/4)r-1+(1/2)r-(11)=0


Domain of the equation: 4)r!=0

r!=0/1

r!=0

r∈R



Domain of the equation: 2)r!=0

r!=0/1

r!=0

r∈R


We add all the numbers together, and all the variables

(+3/4)r+(+1/2)r-1-11=0

We add all the numbers together, and all the variables

(+3/4)r+(+1/2)r-12=0

We multiply parentheses

3r^2+r^2-12=0

We add all the numbers together, and all the variables

4r^2-12=0

a = 4; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·4·(-12)
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{3}}{2*4}=\frac{0-8\sqrt{3}}{8}
=-\frac{8\sqrt{3}}{8}
=-\sqrt{3}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{3}}{2*4}=\frac{0+8\sqrt{3}}{8}
=\frac{8\sqrt{3}}{8}
=\sqrt{3}
$