(3/2b)-(3/5b)=1

Solution for (3/2b)-(3/5b)=1 equation:

(3/2b)-(3/5b)=1

We move all terms to the left:

(3/2b)-(3/5b)-(1)=0


Domain of the equation: 2b)!=0

b!=0/1

b!=0

b∈R



Domain of the equation: 5b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

(+3/2b)-(+3/5b)-1=0

We get rid of parentheses

3/2b-3/5b-1=0

We calculate fractions


15b/10b^2+(-6b)/10b^2-1=0

We multiply all the terms by the denominator


15b+(-6b)-1*10b^2=0

Wy multiply elements

-10b^2+15b+(-6b)=0

We get rid of parentheses

-10b^2+15b-6b=0

We add all the numbers together, and all the variables

-10b^2+9b=0

a = -10; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-10)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-10}=\frac{-18}{-20}
=9/10
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-10}=\frac{0}{-20}
=0
$