8x+(x-7)=9x-(3+4x)

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Solution for 8x+(x-7)=9x-(3+4x) equation: 



8x+(x-7)=9x-(3+4x)

We move all terms to the left:

8x+(x-7)-(9x-(3+4x))=0

We add all the numbers together, and all the variables

8x+(x-7)-(9x-(4x+3))=0

We get rid of parentheses

8x+x-(9x-(4x+3))-7=0



We calculate terms in parentheses: -(9x-(4x+3)), so:

9x-(4x+3)

We get rid of parentheses

9x-4x-3

We add all the numbers together, and all the variables

5x-3

Back to the equation:

-(5x-3)



We add all the numbers together, and all the variables

9x-(5x-3)-7=0

We get rid of parentheses

9x-5x+3-7=0

We add all the numbers together, and all the variables

4x-4=0

We move all terms containing x to the left, all other terms to the right

4x=4

x=4/4

x=1

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