(3-y)(5y-2)=0

Solution for (3-y)(5y-2)=0 equation:

(3-y)(5y-2)=0

We add all the numbers together, and all the variables

(-1y+3)(5y-2)=0

We multiply parentheses ..

(-5y^2+2y+15y-6)=0

We get rid of parentheses

-5y^2+2y+15y-6=0

We add all the numbers together, and all the variables

-5y^2+17y-6=0

a = -5; b = 17; c = -6;
Δ = b2-4ac
Δ = 172-4·(-5)·(-6)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-13}{2*-5}=\frac{-30}{-10}
=+3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+13}{2*-5}=\frac{-4}{-10}
=2/5
$