-3b+26=-6(6b+1)+b

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Solution for -3b+26=-6(6b+1)+b equation: 



-3b+26=-6(6b+1)+b

We move all terms to the left:

-3b+26-(-6(6b+1)+b)=0



We calculate terms in parentheses: -(-6(6b+1)+b), so:

-6(6b+1)+b

We add all the numbers together, and all the variables

b-6(6b+1)

We multiply parentheses

b-36b-6

We add all the numbers together, and all the variables

-35b-6

Back to the equation:

-(-35b-6)



We get rid of parentheses

-3b+35b+6+26=0

We add all the numbers together, and all the variables

32b+32=0

We move all terms containing b to the left, all other terms to the right

32b=-32

b=-32/32

b=-1

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