12(m+2)-4+3m=4(4m+4)-m

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Solution for 12(m+2)-4+3m=4(4m+4)-m equation: 



12(m+2)-4+3m=4(4m+4)-m

We move all terms to the left:

12(m+2)-4+3m-(4(4m+4)-m)=0

We add all the numbers together, and all the variables

3m+12(m+2)-(4(4m+4)-m)-4=0

We multiply parentheses

3m+12m-(4(4m+4)-m)+24-4=0



We calculate terms in parentheses: -(4(4m+4)-m), so:

4(4m+4)-m

We add all the numbers together, and all the variables

-1m+4(4m+4)

We multiply parentheses

-1m+16m+16

We add all the numbers together, and all the variables

15m+16

Back to the equation:

-(15m+16)



We add all the numbers together, and all the variables

15m-(15m+16)+20=0

We get rid of parentheses

15m-15m-16+20=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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