(3*6/2)v+10=(3*3*3)v+9

Solution for (3*6/2)v+10=(3*3*3)v+9 equation:

(3*6/2)v+10=(3*3*3)v+9

We move all terms to the left:

(3*6/2)v+10-((3*3*3)v+9)=0


Domain of the equation: 2)v!=0

v!=0/1

v!=0

v∈R


We add all the numbers together, and all the variables

(+3*6/2)v-(27v+9)+10=0

We multiply parentheses

18v^2-(27v+9)+10=0

We get rid of parentheses

18v^2-27v-9+10=0

We add all the numbers together, and all the variables

18v^2-27v+1=0

a = 18; b = -27; c = +1;
Δ = b2-4ac
Δ = -272-4·18·1
Δ = 657
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{657}=\sqrt{9*73}=\sqrt{9}*\sqrt{73}=3\sqrt{73}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-3\sqrt{73}}{2*18}=\frac{27-3\sqrt{73}}{36}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+3\sqrt{73}}{2*18}=\frac{27+3\sqrt{73}}{36}
$