(3)/(y)-(1)/(12)=(7)/(4y)

Solution for (3)/(y)-(1)/(12)=(7)/(4y) equation:

(3)/(y)-(1)/(12)=(7)/(4y)

We move all terms to the left:

(3)/(y)-(1)/(12)-((7)/(4y))=0


Domain of the equation: y!=0

y∈R



Domain of the equation: 4y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

3/y-(+7/4y)-1/12=0

We get rid of parentheses

3/y-7/4y-1/12=0

We calculate fractions


(-16y^2)/48y^2+144y/48y^2+(-84y)/48y^2=0

We multiply all the terms by the denominator


(-16y^2)+144y+(-84y)=0

We get rid of parentheses

-16y^2+144y-84y=0

We add all the numbers together, and all the variables

-16y^2+60y=0

a = -16; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·(-16)·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*-16}=\frac{-120}{-32}
=3+3/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*-16}=\frac{0}{-32}
=0
$