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(2x+6)(4x-3)=0
We multiply parentheses ..
(+8x^2-6x+24x-18)=0
We get rid of parentheses
8x^2-6x+24x-18=0
We add all the numbers together, and all the variables
8x^2+18x-18=0
a = 8; b = 18; c = -18;
Δ = b2-4ac
Δ = 182-4·8·(-18)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-30}{2*8}=\frac{-48}{16} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+30}{2*8}=\frac{12}{16} =3/4 $
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