3(9-b)-42=27b-5(3+6b)

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Solution for 3(9-b)-42=27b-5(3+6b) equation: 



3(9-b)-42=27b-5(3+6b)

We move all terms to the left:

3(9-b)-42-(27b-5(3+6b))=0

We add all the numbers together, and all the variables

3(-1b+9)-(27b-5(6b+3))-42=0

We multiply parentheses

-3b-(27b-5(6b+3))+27-42=0



We calculate terms in parentheses: -(27b-5(6b+3)), so:

27b-5(6b+3)

We multiply parentheses

27b-30b-15

We add all the numbers together, and all the variables

-3b-15

Back to the equation:

-(-3b-15)



We add all the numbers together, and all the variables

-3b-(-3b-15)-15=0

We get rid of parentheses

-3b+3b+15-15=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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