(3)(y+3)=(5)(y+1)

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Solution for (3)(y+3)=(5)(y+1) equation: 



(3)(y+3)=(5)(y+1)

We move all terms to the left:

(3)(y+3)-((5)(y+1))=0

We multiply parentheses

3y-(5(y+1))+9=0



We calculate terms in parentheses: -(5(y+1)), so:

5(y+1)

We multiply parentheses

5y+5

Back to the equation:

-(5y+5)



We get rid of parentheses

3y-5y-5+9=0

We add all the numbers together, and all the variables

-2y+4=0

We move all terms containing y to the left, all other terms to the right

-2y=-4

y=-4/-2

y=+2

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