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(3)(2x-7)=(5)(x-3)
We move all terms to the left:
(3)(2x-7)-((5)(x-3))=0
We multiply parentheses
6x-(5(x-3))-21=0
We calculate terms in parentheses: -(5(x-3)), so:We get rid of parentheses
5(x-3)
We multiply parentheses
5x-15
Back to the equation:
-(5x-15)
6x-5x+15-21=0
We add all the numbers together, and all the variables
x-6=0
We move all terms containing x to the left, all other terms to the right
x=6
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