(2y-1)(2y-2)=0

Solution for (2y-1)(2y-2)=0 equation:

(2y-1)(2y-2)=0

We multiply parentheses ..

(+4y^2-4y-2y+2)=0

We get rid of parentheses

4y^2-4y-2y+2=0

We add all the numbers together, and all the variables

4y^2-6y+2=0

a = 4; b = -6; c = +2;
Δ = b2-4ac
Δ = -62-4·4·2
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2}{2*4}=\frac{4}{8}
=1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2}{2*4}=\frac{8}{8}
=1
$