-(4x+3)+2(6x-4)=3x-62

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Solution for -(4x+3)+2(6x-4)=3x-62 equation: 



-(4x+3)+2(6x-4)=3x-62

We move all terms to the left:

-(4x+3)+2(6x-4)-(3x-62)=0

We multiply parentheses

-(4x+3)+12x-(3x-62)-8=0

We get rid of parentheses

-4x+12x-3x-3+62-8=0

We add all the numbers together, and all the variables

5x+51=0

We move all terms containing x to the left, all other terms to the right

5x=-51

x=-51/5

x=-10+1/5

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