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1/3x+4x=91
We move all terms to the left:
1/3x+4x-(91)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
4x+1/3x-91=0
We multiply all the terms by the denominator
4x*3x-91*3x+1=0
Wy multiply elements
12x^2-273x+1=0
a = 12; b = -273; c = +1;
Δ = b2-4ac
Δ = -2732-4·12·1
Δ = 74481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-273)-\sqrt{74481}}{2*12}=\frac{273-\sqrt{74481}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-273)+\sqrt{74481}}{2*12}=\frac{273+\sqrt{74481}}{24} $
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