(2y+5)(4)=(3y+11)(5)

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Solution for (2y+5)(4)=(3y+11)(5) equation: 



(2y+5)(4)=(3y+11)(5)

We move all terms to the left:

(2y+5)(4)-((3y+11)(5))=0

We multiply parentheses

8y-((3y+11)5)+20=0



We calculate terms in parentheses: -((3y+11)5), so:

(3y+11)5

We multiply parentheses

15y+55

Back to the equation:

-(15y+55)



We get rid of parentheses

8y-15y-55+20=0

We add all the numbers together, and all the variables

-7y-35=0

We move all terms containing y to the left, all other terms to the right

-7y=35

y=35/-7

y=-5

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