(2x-6)-4(3x+2)=6-2(8x+1)

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Solution for (2x-6)-4(3x+2)=6-2(8x+1) equation: 



(2x-6)-4(3x+2)=6-2(8x+1)

We move all terms to the left:

(2x-6)-4(3x+2)-(6-2(8x+1))=0

We multiply parentheses

(2x-6)-12x-(6-2(8x+1))-8=0

We get rid of parentheses

2x-12x-(6-2(8x+1))-6-8=0



We calculate terms in parentheses: -(6-2(8x+1)), so:

6-2(8x+1)

determiningTheFunctionDomain
-2(8x+1)+6

We multiply parentheses

-16x-2+6

We add all the numbers together, and all the variables

-16x+4

Back to the equation:

-(-16x+4)



We add all the numbers together, and all the variables

-10x-(-16x+4)-14=0

We get rid of parentheses

-10x+16x-4-14=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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