5(3-2(1-4x))+8x=-1+6(8x+1)

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Solution for 5(3-2(1-4x))+8x=-1+6(8x+1) equation: 



5(3-2(1-4x))+8x=-1+6(8x+1)

We move all terms to the left:

5(3-2(1-4x))+8x-(-1+6(8x+1))=0

We add all the numbers together, and all the variables

5(3-2(-4x+1))+8x-(-1+6(8x+1))=0

We add all the numbers together, and all the variables

8x+5(3-2(-4x+1))-(-1+6(8x+1))=0



We calculate terms in parentheses: -(-1+6(8x+1)), so:

-1+6(8x+1)

determiningTheFunctionDomain
6(8x+1)-1

We multiply parentheses

48x+6-1

We add all the numbers together, and all the variables

48x+5

Back to the equation:

-(48x+5)



We get rid of parentheses

8x+5(3-2(-4x+1))-48x-5=0

We add all the numbers together, and all the variables

-40x+5(3-2(-4x+1))-5=0

We move all terms containing x to the left, all other terms to the right

-40x+5(3-2(-4x+1))=5

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