16+4x=3(-x+2)-18

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Solution for 16+4x=3(-x+2)-18 equation: 



16+4x=3(-x+2)-18

We move all terms to the left:

16+4x-(3(-x+2)-18)=0

We add all the numbers together, and all the variables

4x-(3(-1x+2)-18)+16=0



We calculate terms in parentheses: -(3(-1x+2)-18), so:

3(-1x+2)-18

We multiply parentheses

-3x+6-18

We add all the numbers together, and all the variables

-3x-12

Back to the equation:

-(-3x-12)



We get rid of parentheses

4x+3x+12+16=0

We add all the numbers together, and all the variables

7x+28=0

We move all terms containing x to the left, all other terms to the right

7x=-28

x=-28/7

x=-4

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