(11x+2)=58+(5x+10)

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Solution for (11x+2)=58+(5x+10) equation: 



(11x+2)=58+(5x+10)

We move all terms to the left:

(11x+2)-(58+(5x+10))=0

We get rid of parentheses

11x-(58+(5x+10))+2=0



We calculate terms in parentheses: -(58+(5x+10)), so:

58+(5x+10)

determiningTheFunctionDomain
(5x+10)+58

We get rid of parentheses

5x+10+58

We add all the numbers together, and all the variables

5x+68

Back to the equation:

-(5x+68)



We get rid of parentheses

11x-5x-68+2=0

We add all the numbers together, and all the variables

6x-66=0

We move all terms containing x to the left, all other terms to the right

6x=66

x=66/6

x=11

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