(2x-4)/(5x-7)=(3)/(8)

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Solution for (2x-4)/(5x-7)=(3)/(8) equation: 



(2x-4)/(5x-7)=(3)/(8)

We move all terms to the left:

(2x-4)/(5x-7)-((3)/(8))=0



Domain of the equation: (5x-7)!=0

We move all terms containing x to the left, all other terms to the right

5x!=7

x!=7/5

x!=1+2/5

x∈R



We add all the numbers together, and all the variables

(2x-4)/(5x-7)-(+3/8)=0

We get rid of parentheses

(2x-4)/(5x-7)-3/8=0

We calculate fractions


(16x-32)/(40x-56)+(-15x+21)/(40x-56)=0

We multiply all the terms by the denominator


(16x-32)+(-15x+21)=0

We get rid of parentheses

16x-15x-32+21=0

We add all the numbers together, and all the variables

x-11=0

We move all terms containing x to the left, all other terms to the right

x=11

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