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X+1/3X=950
We move all terms to the left:
X+1/3X-(950)=0
Domain of the equation: 3X!=0We multiply all the terms by the denominator
X!=0/3
X!=0
X∈R
X*3X-950*3X+1=0
Wy multiply elements
3X^2-2850X+1=0
a = 3; b = -2850; c = +1;
Δ = b2-4ac
Δ = -28502-4·3·1
Δ = 8122488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8122488}=\sqrt{484*16782}=\sqrt{484}*\sqrt{16782}=22\sqrt{16782}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2850)-22\sqrt{16782}}{2*3}=\frac{2850-22\sqrt{16782}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2850)+22\sqrt{16782}}{2*3}=\frac{2850+22\sqrt{16782}}{6} $
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