2(y+3)=-8y+6

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Solution for 2(y+3)=-8y+6 equation: 



2(y+3)=-8y+6

We move all terms to the left:

2(y+3)-(-8y+6)=0

We multiply parentheses

2y-(-8y+6)+6=0

We get rid of parentheses

2y+8y-6+6=0

We add all the numbers together, and all the variables

10y=0

y=0/10

y=0

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