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(2x-3.8)(4.2+3x)=0
We add all the numbers together, and all the variables
(2x-3.8)(3x+4.2)=0
We multiply parentheses ..
(+6x^2+8.4x-11.4x-15.96)=0
We get rid of parentheses
6x^2+8.4x-11.4x-15.96=0
We add all the numbers together, and all the variables
6x^2-3x-15.96=0
a = 6; b = -3; c = -15.96;
Δ = b2-4ac
Δ = -32-4·6·(-15.96)
Δ = 392.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{392.04}}{2*6}=\frac{3-\sqrt{392.04}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{392.04}}{2*6}=\frac{3+\sqrt{392.04}}{12} $
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