(2x-3)3=(x-2)2

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Solution for (2x-3)3=(x-2)2 equation: 



(2x-3)3=(x-2)2

We move all terms to the left:

(2x-3)3-((x-2)2)=0

We multiply parentheses

6x-((x-2)2)-9=0



We calculate terms in parentheses: -((x-2)2), so:

(x-2)2

We multiply parentheses

2x-4

Back to the equation:

-(2x-4)



We get rid of parentheses

6x-2x+4-9=0

We add all the numbers together, and all the variables

4x-5=0

We move all terms containing x to the left, all other terms to the right

4x=5

x=5/4

x=1+1/4

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