If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8x(5x+2)=27
We move all terms to the left:
8x(5x+2)-(27)=0
We multiply parentheses
40x^2+16x-27=0
a = 40; b = 16; c = -27;
Δ = b2-4ac
Δ = 162-4·40·(-27)
Δ = 4576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4576}=\sqrt{16*286}=\sqrt{16}*\sqrt{286}=4\sqrt{286}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4\sqrt{286}}{2*40}=\frac{-16-4\sqrt{286}}{80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4\sqrt{286}}{2*40}=\frac{-16+4\sqrt{286}}{80} $
| (16-40x)^3=-1000 | | 5(-3x-2)-1(x-3)=-4(4x+5)+13 | | 3x+3=3(x+1 | | 60=4(k+3)+2(k-3 | | -10=2-(9-c) | | 5/2(m+2)=15m-2 | | x2=12x–40 | | -3(1+r)=15 | | .13x=100 | | 20=-5x5 | | 6y-13y-6=36 | | 12^(x-3)=1 | | 4x*5x=27 | | 5+5x3=30 | | 9X-8y=32 | | 4x4+35x2-9=0 | | 7x+2=108 | | 3x+30=7x-20 | | 345-7532+6588765635=x | | 3(x+6)^2=33 | | 58=x-27 | | x^2+8×+2=0 | | 6z-2=118 | | 3/2-8y=1/4+2y | | 3y-8=118 | | 3(5p-3)=5(p-10) | | x4-16x2=x2+18 | | 22-9+w=-14 | | 5+0.2x=3 | | 23-4(3-x)=-17 | | 3x-2((x+4)=-7 | | 3(6+2m)=4(3m=12) |