5(-3x-2)-1(x-3)=-4(4x+5)+13

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Solution for 5(-3x-2)-1(x-3)=-4(4x+5)+13 equation: 



5(-3x-2)-1(x-3)=-4(4x+5)+13

We move all terms to the left:

5(-3x-2)-1(x-3)-(-4(4x+5)+13)=0

We multiply parentheses

-15x-1(x-3)-(-4(4x+5)+13)-10=0



We calculate terms in parentheses: -(-4(4x+5)+13), so:

-4(4x+5)+13

We multiply parentheses

-16x-20+13

We add all the numbers together, and all the variables

-16x-7

Back to the equation:

-(-16x-7)



We get rid of parentheses

-15x-1(x-3)+16x+7-10=0

We add all the numbers together, and all the variables

x-1(x-3)-3=0

We move all terms containing x to the left, all other terms to the right

x-1(x-3)=3

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