(2x-3)(-x+7)+13=4(-1/4x2+3x)+x(-x+4)

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Solution for (2x-3)(-x+7)+13=4(-1/4x2+3x)+x(-x+4) equation: 



(2x-3)(-x+7)+13=4(-1/4x^2+3x)+x(-x+4)

We move all terms to the left:

(2x-3)(-x+7)+13-(4(-1/4x^2+3x)+x(-x+4))=0



Domain of the equation: 4x^2+3x)+x(-x+4))!=0

x∈R



We add all the numbers together, and all the variables

(2x-3)(-1x+7)-(4(-1/4x^2+3x)+x(-1x+4))+13=0

We multiply parentheses ..

(-2x^2+14x+3x-21)-(4(-1/4x^2+3x)+x(-1x+4))+13=0

We multiply all the terms by the denominator


((-2x^2+14x+3x-21))*4x^2+3x)+x(-1x+13*4x^2+3x)+x(-1x-1+4))-(4(+4))=0

We add all the numbers together, and all the variables

((-2x^2+14x+3x-21))*4x^2+3x)+x(-1x+13*4x^2+3x)+x(-1x+3))-(44)=0

We add all the numbers together, and all the variables

((-2x^2+14x+3x-21))*4x^2-2x+3x)+x(+13*4x^2+3x)+x(=0

Wy multiply elements

((-2x^2+14x+3x-21))*4x^2+52x^2-2x+3x)+x(+3x)+x(=0

We add all the numbers together, and all the variables

52x^2+((-2x^2+14x+3x-21))*4x^2-2x+3x)+x(+3x)+x(=0

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