88(t+2)-3(t-4)=6(t-7)+8

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Solution for 88(t+2)-3(t-4)=6(t-7)+8 equation: 



88(t+2)-3(t-4)=6(t-7)+8

We move all terms to the left:

88(t+2)-3(t-4)-(6(t-7)+8)=0

We multiply parentheses

88t-3t-(6(t-7)+8)+176+12=0



We calculate terms in parentheses: -(6(t-7)+8), so:

6(t-7)+8

We multiply parentheses

6t-42+8

We add all the numbers together, and all the variables

6t-34

Back to the equation:

-(6t-34)



We add all the numbers together, and all the variables

85t-(6t-34)+188=0

We get rid of parentheses

85t-6t+34+188=0

We add all the numbers together, and all the variables

79t+222=0

We move all terms containing t to the left, all other terms to the right

79t=-222

t=-222/79

t=-2+64/79

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