1/4(32t-12)=8t+13

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Solution for 1/4(32t-12)=8t+13 equation: 



1/4(32t-12)=8t+13

We move all terms to the left:

1/4(32t-12)-(8t+13)=0



Domain of the equation: 4(32t-12)!=0

t∈R



We get rid of parentheses

1/4(32t-12)-8t-13=0

We multiply all the terms by the denominator


-8t*4(32t-12)-13*4(32t-12)+1=0

Wy multiply elements

-32t^2(3-52t(3+1=0

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