(2x-10)=(3x-65)

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Solution for (2x-10)=(3x-65) equation: 



(2x-10)=(3x-65)

We move all terms to the left:

(2x-10)-((3x-65))=0

We get rid of parentheses

2x-((3x-65))-10=0



We calculate terms in parentheses: -((3x-65)), so:

(3x-65)

We get rid of parentheses

3x-65

Back to the equation:

-(3x-65)



We get rid of parentheses

2x-3x+65-10=0

We add all the numbers together, and all the variables

-1x+55=0

We move all terms containing x to the left, all other terms to the right

-x=-55

x=-55/-1

x=+55

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