(2x-1)+(3x+1)=(x+5)

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Solution for (2x-1)+(3x+1)=(x+5) equation: 



(2x-1)+(3x+1)=(x+5)

We move all terms to the left:

(2x-1)+(3x+1)-((x+5))=0

We get rid of parentheses

2x+3x-((x+5))-1+1=0



We calculate terms in parentheses: -((x+5)), so:

(x+5)

We get rid of parentheses

x+5

Back to the equation:

-(x+5)



We add all the numbers together, and all the variables

5x-(x+5)=0

We get rid of parentheses

5x-x-5=0

We add all the numbers together, and all the variables

4x-5=0

We move all terms containing x to the left, all other terms to the right

4x=5

x=5/4

x=1+1/4

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