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3x-x-5=(x-2)-9
We move all terms to the left:
3x-x-5-((x-2)-9)=0
We add all the numbers together, and all the variables
2x-((x-2)-9)-5=0
We calculate terms in parentheses: -((x-2)-9), so:We get rid of parentheses
(x-2)-9
We get rid of parentheses
x-2-9
We add all the numbers together, and all the variables
x-11
Back to the equation:
-(x-11)
2x-x+11-5=0
We add all the numbers together, and all the variables
x+6=0
We move all terms containing x to the left, all other terms to the right
x=-6
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