(4x-4)+(x+2)=(4x+2)

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Solution for (4x-4)+(x+2)=(4x+2) equation: 



(4x-4)+(x+2)=(4x+2)

We move all terms to the left:

(4x-4)+(x+2)-((4x+2))=0

We get rid of parentheses

4x+x-((4x+2))-4+2=0



We calculate terms in parentheses: -((4x+2)), so:

(4x+2)

We get rid of parentheses

4x+2

Back to the equation:

-(4x+2)



We add all the numbers together, and all the variables

5x-(4x+2)-2=0

We get rid of parentheses

5x-4x-2-2=0

We add all the numbers together, and all the variables

x-4=0

We move all terms containing x to the left, all other terms to the right

x=4

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