(2x-(7-5x))/9x-(3+4x))=7/6

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Solution for (2x-(7-5x))/9x-(3+4x))=7/6 equation: 



(2x-(7-5x))/9x-(3+4x))=7/6

We move all terms to the left:

(2x-(7-5x))/9x-(3+4x))-(7/6)=0



Domain of the equation: 9x!=0

x!=0/9

x!=0

x∈R



We add all the numbers together, and all the variables

(2x-(-5x+7))/9x-(4x+3))-(+7/6)=0

We calculate fractions


-(4x+3))-(+32x/54x^2+63x/54x^2=0

We multiply all the terms by the denominator


-((4x+3))-()*54x^2+32x+63x=0



We calculate terms in parentheses: -((4x+3)), so:

(4x+3)

We get rid of parentheses

4x+3

Back to the equation:

-(4x+3)



We add all the numbers together, and all the variables

95x-(4x+3)-()*54x^2=0

We get rid of parentheses

95x-4x-()*54x^2-3=0

We add all the numbers together, and all the variables

91x-()*54x^2-3=0

We move all terms containing x to the left, all other terms to the right

91x-()*54x^2=3

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