2(4x+3)+x=4(x+4)

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Solution for 2(4x+3)+x=4(x+4) equation: 



2(4x+3)+x=4(x+4)

We move all terms to the left:

2(4x+3)+x-(4(x+4))=0

We add all the numbers together, and all the variables

x+2(4x+3)-(4(x+4))=0

We multiply parentheses

x+8x-(4(x+4))+6=0



We calculate terms in parentheses: -(4(x+4)), so:

4(x+4)

We multiply parentheses

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

9x-(4x+16)+6=0

We get rid of parentheses

9x-4x-16+6=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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