3(7-4x)=1-4(x+5)

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Solution for 3(7-4x)=1-4(x+5) equation: 



3(7-4x)=1-4(x+5)

We move all terms to the left:

3(7-4x)-(1-4(x+5))=0

We add all the numbers together, and all the variables

3(-4x+7)-(1-4(x+5))=0

We multiply parentheses

-12x-(1-4(x+5))+21=0



We calculate terms in parentheses: -(1-4(x+5)), so:

1-4(x+5)

determiningTheFunctionDomain
-4(x+5)+1

We multiply parentheses

-4x-20+1

We add all the numbers together, and all the variables

-4x-19

Back to the equation:

-(-4x-19)



We get rid of parentheses

-12x+4x+19+21=0

We add all the numbers together, and all the variables

-8x+40=0

We move all terms containing x to the left, all other terms to the right

-8x=-40

x=-40/-8

x=+5

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