(2x+5)/4=(x-3)/6

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Solution for (2x+5)/4=(x-3)/6 equation:



(2x+5)/4=(x-3)/6
We move all terms to the left:
(2x+5)/4-((x-3)/6)=0
We calculate fractions
2x/()+(-((x-3)*4)/()=0
We calculate terms in parentheses: +(-((x-3)*4)/(), so:
-((x-3)*4)/(
We multiply all the terms by the denominator
-((x-3)*4)
We calculate terms in parentheses: -((x-3)*4), so:
(x-3)*4
We multiply parentheses
4x-12
Back to the equation:
-(4x-12)
We get rid of parentheses
-4x+12
Back to the equation:
+(-4x+12)
We get rid of parentheses
2x/()-4x+12=0
We multiply all the terms by the denominator
2x-4x*()+12*()=0
We add all the numbers together, and all the variables
2x-4x*()=0

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