3(w-5)-2(1-w)=3-3(4-w)

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Solution for 3(w-5)-2(1-w)=3-3(4-w) equation: 



3(w-5)-2(1-w)=3-3(4-w)

We move all terms to the left:

3(w-5)-2(1-w)-(3-3(4-w))=0

We add all the numbers together, and all the variables

3(w-5)-2(-1w+1)-(3-3(-1w+4))=0

We multiply parentheses

3w+2w-(3-3(-1w+4))-15-2=0



We calculate terms in parentheses: -(3-3(-1w+4)), so:

3-3(-1w+4)

determiningTheFunctionDomain
-3(-1w+4)+3

We multiply parentheses

3w-12+3

We add all the numbers together, and all the variables

3w-9

Back to the equation:

-(3w-9)



We add all the numbers together, and all the variables

5w-(3w-9)-17=0

We get rid of parentheses

5w-3w+9-17=0

We add all the numbers together, and all the variables

2w-8=0

We move all terms containing w to the left, all other terms to the right

2w=8

w=8/2

w=4

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