4(2x-7)-5=4(x-4)+3

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Solution for 4(2x-7)-5=4(x-4)+3 equation: 



4(2x-7)-5=4(x-4)+3

We move all terms to the left:

4(2x-7)-5-(4(x-4)+3)=0

We multiply parentheses

8x-(4(x-4)+3)-28-5=0



We calculate terms in parentheses: -(4(x-4)+3), so:

4(x-4)+3

We multiply parentheses

4x-16+3

We add all the numbers together, and all the variables

4x-13

Back to the equation:

-(4x-13)



We add all the numbers together, and all the variables

8x-(4x-13)-33=0

We get rid of parentheses

8x-4x+13-33=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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