(2x+3)/2=(7x-2)/3

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Solution for (2x+3)/2=(7x-2)/3 equation: 



(2x+3)/2=(7x-2)/3

We move all terms to the left:

(2x+3)/2-((7x-2)/3)=0

We calculate fractions


2x/()+(-((7x-2)*2)/()=0



We calculate terms in parentheses: +(-((7x-2)*2)/(), so:

-((7x-2)*2)/(

We multiply all the terms by the denominator


-((7x-2)*2)



We calculate terms in parentheses: -((7x-2)*2), so:

(7x-2)*2

We multiply parentheses

14x-4

Back to the equation:

-(14x-4)



We get rid of parentheses

-14x+4

Back to the equation:

+(-14x+4)



We get rid of parentheses

2x/()-14x+4=0

We multiply all the terms by the denominator


2x-14x*()+4*()=0

We add all the numbers together, and all the variables

2x-14x*()=0

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