13x+2-(x-3)=x-5-3(x+12)

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Solution for 13x+2-(x-3)=x-5-3(x+12) equation: 



13x+2-(x-3)=x-5-3(x+12)

We move all terms to the left:

13x+2-(x-3)-(x-5-3(x+12))=0

We get rid of parentheses

13x-x-(x-5-3(x+12))+3+2=0



We calculate terms in parentheses: -(x-5-3(x+12)), so:

x-5-3(x+12)

determiningTheFunctionDomain
x-3(x+12)-5

We multiply parentheses

x-3x-36-5

We add all the numbers together, and all the variables

-2x-41

Back to the equation:

-(-2x-41)



We add all the numbers together, and all the variables

12x-(-2x-41)+5=0

We get rid of parentheses

12x+2x+41+5=0

We add all the numbers together, and all the variables

14x+46=0

We move all terms containing x to the left, all other terms to the right

14x=-46

x=-46/14

x=-3+2/7

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