(2x+2)=(8x-16)=(3x+6)

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Solution for (2x+2)=(8x-16)=(3x+6) equation: 



(2x+2)=(8x-16)=(3x+6)

We move all terms to the left:

(2x+2)-((8x-16))=0

We get rid of parentheses

2x-((8x-16))+2=0



We calculate terms in parentheses: -((8x-16)), so:

(8x-16)

We get rid of parentheses

8x-16

Back to the equation:

-(8x-16)



We get rid of parentheses

2x-8x+16+2=0

We add all the numbers together, and all the variables

-6x+18=0

We move all terms containing x to the left, all other terms to the right

-6x=-18

x=-18/-6

x=+3

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