6(u+3)=-2(5u-6)+7u

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Solution for 6(u+3)=-2(5u-6)+7u equation: 



6(u+3)=-2(5u-6)+7u

We move all terms to the left:

6(u+3)-(-2(5u-6)+7u)=0

We multiply parentheses

6u-(-2(5u-6)+7u)+18=0



We calculate terms in parentheses: -(-2(5u-6)+7u), so:

-2(5u-6)+7u

We add all the numbers together, and all the variables

7u-2(5u-6)

We multiply parentheses

7u-10u+12

We add all the numbers together, and all the variables

-3u+12

Back to the equation:

-(-3u+12)



We get rid of parentheses

6u+3u-12+18=0

We add all the numbers together, and all the variables

9u+6=0

We move all terms containing u to the left, all other terms to the right

9u=-6

u=-6/9

u=-2/3

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