-2(y+1)=4y-8+4(3y+4)

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Solution for -2(y+1)=4y-8+4(3y+4) equation: 



-2(y+1)=4y-8+4(3y+4)

We move all terms to the left:

-2(y+1)-(4y-8+4(3y+4))=0

We multiply parentheses

-2y-(4y-8+4(3y+4))-2=0



We calculate terms in parentheses: -(4y-8+4(3y+4)), so:

4y-8+4(3y+4)

determiningTheFunctionDomain
4y+4(3y+4)-8

We multiply parentheses

4y+12y+16-8

We add all the numbers together, and all the variables

16y+8

Back to the equation:

-(16y+8)



We get rid of parentheses

-2y-16y-8-2=0

We add all the numbers together, and all the variables

-18y-10=0

We move all terms containing y to the left, all other terms to the right

-18y=10

y=10/-18

y=-5/9

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