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(2x+15)+(3x-20)x+(x+15)=360
We move all terms to the left:
(2x+15)+(3x-20)x+(x+15)-(360)=0
We multiply parentheses
3x^2+(2x+15)-20x+(x+15)-360=0
We get rid of parentheses
3x^2+2x-20x+x+15+15-360=0
We add all the numbers together, and all the variables
3x^2-17x-330=0
a = 3; b = -17; c = -330;
Δ = b2-4ac
Δ = -172-4·3·(-330)
Δ = 4249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{4249}}{2*3}=\frac{17-\sqrt{4249}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{4249}}{2*3}=\frac{17+\sqrt{4249}}{6} $
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